Fearfulways @ Argent Dawn (RP)
Last updated: Tue Sep 11th, 10:44pm (PST)
Members: 221 (+21 Alts)
  • Average Level: 49
  • Level 70: 96
  • Level 60-69: 35
  • Level 50-59: 12
  • Level 40-49: 17
  • Level 30-39: 17
  • Level 1-29: 65
WoW Server Status
Addons

Poisons
Level Name
350/350
Noite

Blacksmithing
Level Name
375/375
Noite
300/375
Makyson

Enchanting
Level Name
120/150
Makeson
90/150
Luzdanoite

Herbalism
Level Name
375/375
Fearfulways

Leatherworking
Level Name
289/300
Shogunate

Mining
Level Name
375/375
Fearfulways
375/375
Noite
304/375
Makyson

Skinning
Level Name
300/300
Shogunate
26/75
Luzdanoite

Tailoring
Level Name
225/225
Makeson

Cooking
Level Name
370/375
Noite
161/225
Shogunate
116/150
Fearfulways
9/75
Makyson

First Aid
Level Name
375/375
Fearfulways
375/375
Noite
319/375
Makyson
300/300
Shogunate
69/150
Makeson

Fishing
Level Name
322/375
Noite
89/150
Shogunate
25/75
Makyson
17/75
Fearfulways



WoWRoster v1.7.3

Props to Celandro, Paleblackness, Pytte, Rubricsinger, and Konkers for the original code used for this site.
WoWRoster home - www.wowroster.net
World of Warcraft and Blizzard Entertainment are trademarks or registered trademarks of Blizzard Entertainment, Inc. in the U.S. and/or other countries. All other trademarks are the property of their respective owners.
Additional Credits


Valid HTML 4.0 Transitional

This page was created in 0.29 seconds with 5 queries executed

SQL Queries
SELECT `config_name`, `config_value` FROM `roster_config` ORDER BY `id` ASC;
SELECT * FROM `roster_guild` WHERE `guild_name` = 'Fearfulways' AND `server` = 'Argent Dawn'
SELECT `guild_id`, `guild_dateupdatedutc` FROM `roster_guild` WHERE `guild_name` = 'Fearfulways' AND `server` ='Argent Dawn'
SELECT IF(`note` LIKE '%alt%',1,0) AS 'isalt',
FLOOR(`level`/10) AS levelgroup,
COUNT(`level`) AS amount,
SUM(`level`) AS sum
FROM `roster_members`
GROUP BY isalt, levelgroup
ORDER BY isalt ASC, levelgroup DESC
SELECT `s`.*, `p`.`name`, `p`.`clientLocale` FROM `roster_skills` s, `roster_players` p
WHERE p.member_id = s.member_id
AND p.guild_id = '1'
AND SUBSTRING_INDEX( s.skill_level, ':', 1 ) > 1
AND skill_name IN ('Alchimie', 'Kräuterkunde', 'Schmiedekunst', 'Bergbau', 'Lederverarbeitung', 'Juwelenschleifen', 'Kürschnerei', 'Schneiderei', 'Verzauberkunst', 'Ingenieurskunst', 'Kochkunst', 'Angeln', 'Erste Hilfe', 'GifteAlchemy', 'Herbalism', 'Blacksmithing', 'Mining', 'Leatherworking', 'Jewelcrafting', 'Skinning', 'Tailoring', 'Enchanting', 'Engineering', 'Cooking', 'Fishing', 'First Aid', 'PoisonsAlquimia', 'Botánica', 'Herrería', 'Minería', 'Peletería', 'Joyería', 'Desollar', 'Sastrería', 'Encantamiento', 'Ingeniería', 'Cocina', 'Pesca', 'Primeros auxilios', 'VenenosAlchimie', 'Herboristerie', 'Forge', 'Minage', 'Travail du cuir', 'Joaillerie', 'Dépeçage', 'Couture', 'Enchantement', 'Ingénierie', 'Cuisine', 'Pêche', 'Premiers soins', 'Poisons')
ORDER BY s.skill_type,s.skill_name,(mid(skill_level FROM 1 FOR (locate(':', skill_level)-1)) + 0) DESC, p.name;